3(r+6)=5r-2(2r-4)

Solution for 3(r+6)=5r-2(2r-4) equation:

3(r+6)=5r-2(2r-4)

We move all terms to the left:

3(r+6)-(5r-2(2r-4))=0

We multiply parentheses

3r-(5r-2(2r-4))+18=0


We calculate terms in parentheses: -(5r-2(2r-4)), so:

5r-2(2r-4)

We multiply parentheses

5r-4r+8

We add all the numbers together, and all the variables

r+8

Back to the equation:

-(r+8)


We get rid of parentheses

3r-r-8+18=0

We add all the numbers together, and all the variables

2r+10=0

We move all terms containing r to the left, all other terms to the right

2r=-10

r=-10/2

r=-5