2y-(7y+5)=6(y+3)-2y

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Solution for 2y-(7y+5)=6(y+3)-2y equation: 



2y-(7y+5)=6(y+3)-2y

We move all terms to the left:

2y-(7y+5)-(6(y+3)-2y)=0

We get rid of parentheses

2y-7y-(6(y+3)-2y)-5=0



We calculate terms in parentheses: -(6(y+3)-2y), so:

6(y+3)-2y

We add all the numbers together, and all the variables

-2y+6(y+3)

We multiply parentheses

-2y+6y+18

We add all the numbers together, and all the variables

4y+18

Back to the equation:

-(4y+18)



We add all the numbers together, and all the variables

-5y-(4y+18)-5=0

We get rid of parentheses

-5y-4y-18-5=0

We add all the numbers together, and all the variables

-9y-23=0

We move all terms containing y to the left, all other terms to the right

-9y=23

y=23/-9

y=-2+5/9

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