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1/4(x-8)+1/2=2/3x+3
We move all terms to the left:
1/4(x-8)+1/2-(2/3x+3)=0
Domain of the equation: 4(x-8)!=0
x∈R
Domain of the equation: 3x+3)!=0We get rid of parentheses
x∈R
1/4(x-8)-2/3x-3+1/2=0
We calculate fractions
12x/(4(x-8)*3x*2)+(-16xx/(4(x-8)*3x*2)+(12x^2x/(4(x-8)*3x*2)-3=0
We can not solve this equation
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