2y+(22y/8)=190

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Solution for 2y+(22y/8)=190 equation: 



2y+(22y/8)=190

We move all terms to the left:

2y+(22y/8)-(190)=0

We add all the numbers together, and all the variables

2y+(+22y/8)-190=0

We get rid of parentheses

2y+22y/8-190=0

We multiply all the terms by the denominator


2y*8+22y-190*8=0

We add all the numbers together, and all the variables

22y+2y*8-1520=0

Wy multiply elements

22y+16y-1520=0

We add all the numbers together, and all the variables

38y-1520=0

We move all terms containing y to the left, all other terms to the right

38y=1520

y=1520/38

y=40

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