2y+(11/8)(y)+(11/8)(y)=190

Solution for 2y+(11/8)(y)+(11/8)(y)=190 equation:

2y+(11/8)(y)+(11/8)(y)=190

We move all terms to the left:

2y+(11/8)(y)+(11/8)(y)-(190)=0


Domain of the equation: 8)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

2y+(+11/8)y+(+11/8)y-190=0

We multiply parentheses

11y^2+11y^2+2y-190=0

We add all the numbers together, and all the variables

22y^2+2y-190=0

a = 22; b = 2; c = -190;
Δ = b2-4ac
Δ = 22-4·22·(-190)
Δ = 16724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16724}=\sqrt{4*4181}=\sqrt{4}*\sqrt{4181}=2\sqrt{4181}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{4181}}{2*22}=\frac{-2-2\sqrt{4181}}{44}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{4181}}{2*22}=\frac{-2+2\sqrt{4181}}{44}
$