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6(x-2)+5x=2(2x+1)
We move all terms to the left:
6(x-2)+5x-(2(2x+1))=0
We add all the numbers together, and all the variables
5x+6(x-2)-(2(2x+1))=0
We multiply parentheses
5x+6x-(2(2x+1))-12=0
We calculate terms in parentheses: -(2(2x+1)), so:We add all the numbers together, and all the variables
2(2x+1)
We multiply parentheses
4x+2
Back to the equation:
-(4x+2)
11x-(4x+2)-12=0
We get rid of parentheses
11x-4x-2-12=0
We add all the numbers together, and all the variables
7x-14=0
We move all terms containing x to the left, all other terms to the right
7x=14
x=14/7
x=2
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