2y(y+18)=180

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Solution for 2y(y+18)=180 equation:



2y(y+18)=180
We move all terms to the left:
2y(y+18)-(180)=0
We multiply parentheses
2y^2+36y-180=0
a = 2; b = 36; c = -180;
Δ = b2-4ac
Δ = 362-4·2·(-180)
Δ = 2736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2736}=\sqrt{144*19}=\sqrt{144}*\sqrt{19}=12\sqrt{19}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12\sqrt{19}}{2*2}=\frac{-36-12\sqrt{19}}{4} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12\sqrt{19}}{2*2}=\frac{-36+12\sqrt{19}}{4} $

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