4(3-3y-1)=40

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Solution for 4(3-3y-1)=40 equation: 



4(3-3y-1)=40

We move all terms to the left:

4(3-3y-1)-(40)=0

We add all the numbers together, and all the variables

4(-3y+2)-40=0

We multiply parentheses

-12y+8-40=0

We add all the numbers together, and all the variables

-12y-32=0

We move all terms containing y to the left, all other terms to the right

-12y=32

y=32/-12

y=-2+2/3

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