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3(x-4)+6=5(x-1)=1
We move all terms to the left:
3(x-4)+6-(5(x-1))=0
We multiply parentheses
3x-(5(x-1))-12+6=0
We calculate terms in parentheses: -(5(x-1)), so:We add all the numbers together, and all the variables
5(x-1)
We multiply parentheses
5x-5
Back to the equation:
-(5x-5)
3x-(5x-5)-6=0
We get rid of parentheses
3x-5x+5-6=0
We add all the numbers together, and all the variables
-2x-1=0
We move all terms containing x to the left, all other terms to the right
-2x=1
x=1/-2
x=-1/2
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