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2x=3+1/5x
We move all terms to the left:
2x-(3+1/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x-(1/5x+3)=0
We get rid of parentheses
2x-1/5x-3=0
We multiply all the terms by the denominator
2x*5x-3*5x-1=0
Wy multiply elements
10x^2-15x-1=0
a = 10; b = -15; c = -1;
Δ = b2-4ac
Δ = -152-4·10·(-1)
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{265}}{2*10}=\frac{15-\sqrt{265}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{265}}{2*10}=\frac{15+\sqrt{265}}{20} $
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