6(5z-1)-5(z+4)=6(z+1)

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Solution for 6(5z-1)-5(z+4)=6(z+1) equation: 



6(5z-1)-5(z+4)=6(z+1)

We move all terms to the left:

6(5z-1)-5(z+4)-(6(z+1))=0

We multiply parentheses

30z-5z-(6(z+1))-6-20=0



We calculate terms in parentheses: -(6(z+1)), so:

6(z+1)

We multiply parentheses

6z+6

Back to the equation:

-(6z+6)



We add all the numbers together, and all the variables

25z-(6z+6)-26=0

We get rid of parentheses

25z-6z-6-26=0

We add all the numbers together, and all the variables

19z-32=0

We move all terms containing z to the left, all other terms to the right

19z=32

z=32/19

z=1+13/19

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