-(9x-4)-2x-9+8=7(x-4)-8x+8+6

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Solution for -(9x-4)-2x-9+8=7(x-4)-8x+8+6 equation: 



-(9x-4)-2x-9+8=7(x-4)-8x+8+6

We move all terms to the left:

-(9x-4)-2x-9+8-(7(x-4)-8x+8+6)=0

We add all the numbers together, and all the variables

-2x-(9x-4)-(7(x-4)-8x+8+6)-1=0

We get rid of parentheses

-2x-9x-(7(x-4)-8x+8+6)+4-1=0



We calculate terms in parentheses: -(7(x-4)-8x+8+6), so:

7(x-4)-8x+8+6

We add all the numbers together, and all the variables

-8x+7(x-4)+14

We multiply parentheses

-8x+7x-28+14

We add all the numbers together, and all the variables

-1x-14

Back to the equation:

-(-1x-14)



We add all the numbers together, and all the variables

-11x-(-1x-14)+3=0

We get rid of parentheses

-11x+1x+14+3=0

We add all the numbers together, and all the variables

-10x+17=0

We move all terms containing x to the left, all other terms to the right

-10x=-17

x=-17/-10

x=1+7/10

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