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2x^2=54
We move all terms to the left:
2x^2-(54)=0
a = 2; b = 0; c = -54;
Δ = b2-4ac
Δ = 02-4·2·(-54)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*2}=\frac{0-12\sqrt{3}}{4} =-\frac{12\sqrt{3}}{4} =-3\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*2}=\frac{0+12\sqrt{3}}{4} =\frac{12\sqrt{3}}{4} =3\sqrt{3} $
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