180-(3x-12)+(2x-10)+(2x-18)=180

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Solution for 180-(3x-12)+(2x-10)+(2x-18)=180 equation: 



180-(3x-12)+(2x-10)+(2x-18)=180

We move all terms to the left:

180-(3x-12)+(2x-10)+(2x-18)-(180)=0

We add all the numbers together, and all the variables

-(3x-12)+(2x-10)+(2x-18)=0

We get rid of parentheses

-3x+2x+2x+12-10-18=0

We add all the numbers together, and all the variables

x-16=0

We move all terms containing x to the left, all other terms to the right

x=16

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