(3x+6)(x-8)=0

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Solution for (3x+6)(x-8)=0 equation:



(3x+6)(x-8)=0
We multiply parentheses ..
(+3x^2-24x+6x-48)=0
We get rid of parentheses
3x^2-24x+6x-48=0
We add all the numbers together, and all the variables
3x^2-18x-48=0
a = 3; b = -18; c = -48;
Δ = b2-4ac
Δ = -182-4·3·(-48)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-30}{2*3}=\frac{-12}{6} =-2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+30}{2*3}=\frac{48}{6} =8 $

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