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2x^2+30x-200=0
a = 2; b = 30; c = -200;
Δ = b2-4ac
Δ = 302-4·2·(-200)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-50}{2*2}=\frac{-80}{4} =-20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+50}{2*2}=\frac{20}{4} =5 $
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