1=4u+3(u+5)

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Solution for 1=4u+3(u+5) equation: 



1=4u+3(u+5)

We move all terms to the left:

1-(4u+3(u+5))=0



We calculate terms in parentheses: -(4u+3(u+5)), so:

4u+3(u+5)

We multiply parentheses

4u+3u+15

We add all the numbers together, and all the variables

7u+15

Back to the equation:

-(7u+15)



We get rid of parentheses

-7u-15+1=0

We add all the numbers together, and all the variables

-7u-14=0

We move all terms containing u to the left, all other terms to the right

-7u=14

u=14/-7

u=-2

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