-22=2(v-3)+6v

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Solution for -22=2(v-3)+6v equation: 



-22=2(v-3)+6v

We move all terms to the left:

-22-(2(v-3)+6v)=0



We calculate terms in parentheses: -(2(v-3)+6v), so:

2(v-3)+6v

We add all the numbers together, and all the variables

6v+2(v-3)

We multiply parentheses

6v+2v-6

We add all the numbers together, and all the variables

8v-6

Back to the equation:

-(8v-6)



We get rid of parentheses

-8v+6-22=0

We add all the numbers together, and all the variables

-8v-16=0

We move all terms containing v to the left, all other terms to the right

-8v=16

v=16/-8

v=-2

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