6(c+1)=4c+8

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Solution for 6(c+1)=4c+8 equation: 



6(c+1)=4c+8

We move all terms to the left:

6(c+1)-(4c+8)=0

We multiply parentheses

6c-(4c+8)+6=0

We get rid of parentheses

6c-4c-8+6=0

We add all the numbers together, and all the variables

2c-2=0

We move all terms containing c to the left, all other terms to the right

2c=2

c=2/2

c=1

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