(3y/7)-(7/8)=(9/56)

Solution for (3y/7)-(7/8)=(9/56) equation:

(3y/7)-(7/8)=(9/56)

We move all terms to the left:

(3y/7)-(7/8)-((9/56))=0

We add all the numbers together, and all the variables

(+3y/7)-(+7/8)-((+9/56))=0

We get rid of parentheses

3y/7-7/8-((+9/56))=0

We calculate fractions


6720y^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

6720y^2/()+2=0

We multiply all the terms by the denominator


6720y^2+2*()=0

We add all the numbers together, and all the variables

6720y^2=0

a = 6720; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6720·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{13440}=0$