2x-8+2(2x+4)=-3(x+4)

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Solution for 2x-8+2(2x+4)=-3(x+4) equation: 



2x-8+2(2x+4)=-3(x+4)

We move all terms to the left:

2x-8+2(2x+4)-(-3(x+4))=0

We multiply parentheses

2x+4x-(-3(x+4))+8-8=0



We calculate terms in parentheses: -(-3(x+4)), so:

-3(x+4)

We multiply parentheses

-3x-12

Back to the equation:

-(-3x-12)



We add all the numbers together, and all the variables

6x-(-3x-12)=0

We get rid of parentheses

6x+3x+12=0

We add all the numbers together, and all the variables

9x+12=0

We move all terms containing x to the left, all other terms to the right

9x=-12

x=-12/9

x=-1+1/3

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