4(d+3)-2(d+7)+4=5(d+2)+7

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Solution for 4(d+3)-2(d+7)+4=5(d+2)+7 equation: 



4(d+3)-2(d+7)+4=5(d+2)+7

We move all terms to the left:

4(d+3)-2(d+7)+4-(5(d+2)+7)=0

We multiply parentheses

4d-2d-(5(d+2)+7)+12-14+4=0



We calculate terms in parentheses: -(5(d+2)+7), so:

5(d+2)+7

We multiply parentheses

5d+10+7

We add all the numbers together, and all the variables

5d+17

Back to the equation:

-(5d+17)



We add all the numbers together, and all the variables

2d-(5d+17)+2=0

We get rid of parentheses

2d-5d-17+2=0

We add all the numbers together, and all the variables

-3d-15=0

We move all terms containing d to the left, all other terms to the right

-3d=15

d=15/-3

d=-5

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