8-(2y-2)=2(y-2)+3y

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Solution for 8-(2y-2)=2(y-2)+3y equation: 



8-(2y-2)=2(y-2)+3y

We move all terms to the left:

8-(2y-2)-(2(y-2)+3y)=0

We get rid of parentheses

-2y-(2(y-2)+3y)+2+8=0



We calculate terms in parentheses: -(2(y-2)+3y), so:

2(y-2)+3y

We add all the numbers together, and all the variables

3y+2(y-2)

We multiply parentheses

3y+2y-4

We add all the numbers together, and all the variables

5y-4

Back to the equation:

-(5y-4)



We add all the numbers together, and all the variables

-2y-(5y-4)+10=0

We get rid of parentheses

-2y-5y+4+10=0

We add all the numbers together, and all the variables

-7y+14=0

We move all terms containing y to the left, all other terms to the right

-7y=-14

y=-14/-7

y=+2

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