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2x-5=2(3+x)
We move all terms to the left:
2x-5-(2(3+x))=0
We add all the numbers together, and all the variables
2x-(2(x+3))-5=0
We calculate terms in parentheses: -(2(x+3)), so:We get rid of parentheses
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
2x-2x-6-5=0
We add all the numbers together, and all the variables
-11!=0
There is no solution for this equation
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