2x+7(x-8)=7(4+x))+8x

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Solution for 2x+7(x-8)=7(4+x))+8x equation: 



2x+7(x-8)=7(4+x))+8x

We move all terms to the left:

2x+7(x-8)-(7(4+x))+8x)=0

We add all the numbers together, and all the variables

2x+7(x-8)-(7(x+4))+8x)=0

We multiply parentheses

2x+7x-(7(x+4))+8x)-56=0



We calculate terms in parentheses: -(7(x+4)), so:

7(x+4)

We multiply parentheses

7x+28

Back to the equation:

-(7x+28)



We add all the numbers together, and all the variables

9x-(7x+28)+8x)-56=0

We get rid of parentheses

9x-7x+8x)-56-28=0

We add all the numbers together, and all the variables

2x+8x)-56-28=0

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