(8/x)+2=(x+4)/(x-6)

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Solution for (8/x)+2=(x+4)/(x-6) equation: 



(8/x)+2=(x+4)/(x-6)

We move all terms to the left:

(8/x)+2-((x+4)/(x-6))=0



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: (x-6))!=0

x∈R



We add all the numbers together, and all the variables

(+8/x)-((x+4)/(x-6))+2=0

We get rid of parentheses

8/x-((x+4)/(x-6))+2=0

We calculate fractions


8x/(-5x^2)+(-((x+4)*x)/(-5x^2)+2=0

We calculate fractions

We do not support expression: x^3

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