2x-5(x-2)=-5+4x-41

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Solution for 2x-5(x-2)=-5+4x-41 equation: 



2x-5(x-2)=-5+4x-41

We move all terms to the left:

2x-5(x-2)-(-5+4x-41)=0

We add all the numbers together, and all the variables

2x-5(x-2)-(4x-46)=0

We multiply parentheses

2x-5x-(4x-46)+10=0

We get rid of parentheses

2x-5x-4x+46+10=0

We add all the numbers together, and all the variables

-7x+56=0

We move all terms containing x to the left, all other terms to the right

-7x=-56

x=-56/-7

x=+8

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