-3(-7y+9)-7y=2(y-4)-1

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Solution for -3(-7y+9)-7y=2(y-4)-1 equation: 



-3(-7y+9)-7y=2(y-4)-1

We move all terms to the left:

-3(-7y+9)-7y-(2(y-4)-1)=0

We add all the numbers together, and all the variables

-7y-3(-7y+9)-(2(y-4)-1)=0

We multiply parentheses

-7y+21y-(2(y-4)-1)-27=0



We calculate terms in parentheses: -(2(y-4)-1), so:

2(y-4)-1

We multiply parentheses

2y-8-1

We add all the numbers together, and all the variables

2y-9

Back to the equation:

-(2y-9)



We add all the numbers together, and all the variables

14y-(2y-9)-27=0

We get rid of parentheses

14y-2y+9-27=0

We add all the numbers together, and all the variables

12y-18=0

We move all terms containing y to the left, all other terms to the right

12y=18

y=18/12

y=1+1/2

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