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1/2(6x-12)=2/3(12x+12)
We move all terms to the left:
1/2(6x-12)-(2/3(12x+12))=0
Domain of the equation: 2(6x-12)!=0
x∈R
Domain of the equation: 3(12x+12))!=0We calculate fractions
x∈R
(3x1/(2(6x-12)*3(12x+12)))+(-4x6/(2(6x-12)*3(12x+12)))=0
We calculate terms in parentheses: +(3x1/(2(6x-12)*3(12x+12))), so:
3x1/(2(6x-12)*3(12x+12))
We multiply all the terms by the denominator
3x1
We add all the numbers together, and all the variables
3x
Back to the equation:
+(3x)
We calculate terms in parentheses: +(-4x6/(2(6x-12)*3(12x+12))), so:
-4x6/(2(6x-12)*3(12x+12))
We multiply all the terms by the denominator
-4x6
We add all the numbers together, and all the variables
-4x^6
We do not support expression: x^6
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