2x-4(x-3)=-8+5x-8

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Solution for 2x-4(x-3)=-8+5x-8 equation: 



2x-4(x-3)=-8+5x-8

We move all terms to the left:

2x-4(x-3)-(-8+5x-8)=0

We add all the numbers together, and all the variables

2x-4(x-3)-(5x-16)=0

We multiply parentheses

2x-4x-(5x-16)+12=0

We get rid of parentheses

2x-4x-5x+16+12=0

We add all the numbers together, and all the variables

-7x+28=0

We move all terms containing x to the left, all other terms to the right

-7x=-28

x=-28/-7

x=+4

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