(2+v)(5v+6)=0

Solution for (2+v)(5v+6)=0 equation:

(2+v)(5v+6)=0

We add all the numbers together, and all the variables

(v+2)(5v+6)=0

We multiply parentheses ..

(+5v^2+6v+10v+12)=0

We get rid of parentheses

5v^2+6v+10v+12=0

We add all the numbers together, and all the variables

5v^2+16v+12=0

a = 5; b = 16; c = +12;
Δ = b2-4ac
Δ = 162-4·5·12
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4}{2*5}=\frac{-20}{10}
=-2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4}{2*5}=\frac{-12}{10}
=-1+1/5
$