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2x-4(x-1)=2(2x-1)+3x
We move all terms to the left:
2x-4(x-1)-(2(2x-1)+3x)=0
We multiply parentheses
2x-4x-(2(2x-1)+3x)+4=0
We calculate terms in parentheses: -(2(2x-1)+3x), so:We add all the numbers together, and all the variables
2(2x-1)+3x
We add all the numbers together, and all the variables
3x+2(2x-1)
We multiply parentheses
3x+4x-2
We add all the numbers together, and all the variables
7x-2
Back to the equation:
-(7x-2)
-2x-(7x-2)+4=0
We get rid of parentheses
-2x-7x+2+4=0
We add all the numbers together, and all the variables
-9x+6=0
We move all terms containing x to the left, all other terms to the right
-9x=-6
x=-6/-9
x=2/3
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