2x-2(3x+2)=8-x

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Solution for 2x-2(3x+2)=8-x equation: 



2x-2(3x+2)=8-x

We move all terms to the left:

2x-2(3x+2)-(8-x)=0

We add all the numbers together, and all the variables

2x-2(3x+2)-(-1x+8)=0

We multiply parentheses

2x-6x-(-1x+8)-4=0

We get rid of parentheses

2x-6x+1x-8-4=0

We add all the numbers together, and all the variables

-3x-12=0

We move all terms containing x to the left, all other terms to the right

-3x=12

x=12/-3

x=-4

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