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(2/3x-7)=(5/6x)
We move all terms to the left:
(2/3x-7)-((5/6x))=0
Domain of the equation: 3x-7)!=0
x∈R
Domain of the equation: 6x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(2/3x-7)-((+5/6x))=0
We get rid of parentheses
2/3x-((+5/6x))-7=0
We calculate fractions
12x/18x^2+(-((+5*3x)/18x^2-7=0
We calculate fractions
We do not support expression: x^4
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