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1/5x=6x-2
We move all terms to the left:
1/5x-(6x-2)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
1/5x-6x+2=0
We multiply all the terms by the denominator
-6x*5x+2*5x+1=0
Wy multiply elements
-30x^2+10x+1=0
a = -30; b = 10; c = +1;
Δ = b2-4ac
Δ = 102-4·(-30)·1
Δ = 220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{220}=\sqrt{4*55}=\sqrt{4}*\sqrt{55}=2\sqrt{55}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{55}}{2*-30}=\frac{-10-2\sqrt{55}}{-60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{55}}{2*-30}=\frac{-10+2\sqrt{55}}{-60} $
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