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2x-(3/3)=3x-(1/6)
We move all terms to the left:
2x-(3/3)-(3x-(1/6))=0
We add all the numbers together, and all the variables
2x-(3x-(+1/6))-1=0
We multiply all the terms by the denominator
2x*6))-(3x-(+1-1*6))=0
We add all the numbers together, and all the variables
2x*6))-(3x-(-5))=0
We add all the numbers together, and all the variables
2x*6))-(3x-(=0
Wy multiply elements
12x^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{24}=0$
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