41-9z=5(z-3)

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Solution for 41-9z=5(z-3) equation: 



41-9z=5(z-3)

We move all terms to the left:

41-9z-(5(z-3))=0



We calculate terms in parentheses: -(5(z-3)), so:

5(z-3)

We multiply parentheses

5z-15

Back to the equation:

-(5z-15)



We get rid of parentheses

-9z-5z+15+41=0

We add all the numbers together, and all the variables

-14z+56=0

We move all terms containing z to the left, all other terms to the right

-14z=-56

z=-56/-14

z=+4

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