3(x+2)=3(1-2x)

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Solution for 3(x+2)=3(1-2x) equation: 



3(x+2)=3(1-2x)

We move all terms to the left:

3(x+2)-(3(1-2x))=0

We add all the numbers together, and all the variables

3(x+2)-(3(-2x+1))=0

We multiply parentheses

3x-(3(-2x+1))+6=0



We calculate terms in parentheses: -(3(-2x+1)), so:

3(-2x+1)

We multiply parentheses

-6x+3

Back to the equation:

-(-6x+3)



We get rid of parentheses

3x+6x-3+6=0

We add all the numbers together, and all the variables

9x+3=0

We move all terms containing x to the left, all other terms to the right

9x=-3

x=-3/9

x=-1/3

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