2x+8(-3-x)=2(-8-x)

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Solution for 2x+8(-3-x)=2(-8-x) equation: 



2x+8(-3-x)=2(-8-x)

We move all terms to the left:

2x+8(-3-x)-(2(-8-x))=0

We add all the numbers together, and all the variables

2x+8(-1x-3)-(2(-1x-8))=0

We multiply parentheses

2x-8x-(2(-1x-8))-24=0



We calculate terms in parentheses: -(2(-1x-8)), so:

2(-1x-8)

We multiply parentheses

-2x-16

Back to the equation:

-(-2x-16)



We add all the numbers together, and all the variables

-6x-(-2x-16)-24=0

We get rid of parentheses

-6x+2x+16-24=0

We add all the numbers together, and all the variables

-4x-8=0

We move all terms containing x to the left, all other terms to the right

-4x=8

x=8/-4

x=-2

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