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1/4y+1=1/6y=-2
We move all terms to the left:
1/4y+1-(1/6y)=0
Domain of the equation: 4y!=0
y!=0/4
y!=0
y∈R
Domain of the equation: 6y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
1/4y-(+1/6y)+1=0
We get rid of parentheses
1/4y-1/6y+1=0
We calculate fractions
6y/24y^2+(-4y)/24y^2+1=0
We multiply all the terms by the denominator
6y+(-4y)+1*24y^2=0
Wy multiply elements
24y^2+6y+(-4y)=0
We get rid of parentheses
24y^2+6y-4y=0
We add all the numbers together, and all the variables
24y^2+2y=0
a = 24; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·24·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*24}=\frac{-4}{48} =-1/12 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*24}=\frac{0}{48} =0 $
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