2z-2z(1+2)=28

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Solution for 2z-2z(1+2)=28 equation: 



2z-2z(1+2)=28

We move all terms to the left:

2z-2z(1+2)-(28)=0

We add all the numbers together, and all the variables

2z-2z3-28=0

We add all the numbers together, and all the variables

-2z^3+2z-28=0

We do not support ezpression: z^3

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