2x+7+4(x-3)=4(x-3)

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Solution for 2x+7+4(x-3)=4(x-3) equation: 



2x+7+4(x-3)=4(x-3)

We move all terms to the left:

2x+7+4(x-3)-(4(x-3))=0

We multiply parentheses

2x+4x-(4(x-3))-12+7=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

6x-(4x-12)-5=0

We get rid of parentheses

6x-4x+12-5=0

We add all the numbers together, and all the variables

2x+7=0

We move all terms containing x to the left, all other terms to the right

2x=-7

x=-7/2

x=-3+1/2

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