5(r-7)=3r+41

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Solution for 5(r-7)=3r+41 equation:



5(r-7)=3r+41
We move all terms to the left:
5(r-7)-(3r+41)=0
We multiply parentheses
5r-(3r+41)-35=0
We get rid of parentheses
5r-3r-41-35=0
We add all the numbers together, and all the variables
2r-76=0
We move all terms containing r to the left, all other terms to the right
2r=76
r=76/2
r=38

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