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-6(3-x)2x=2x-1-15x
We move all terms to the left:
-6(3-x)2x-(2x-1-15x)=0
We add all the numbers together, and all the variables
-6(-1x+3)2x-(-13x-1)=0
We multiply parentheses
12x^2-36x-(-13x-1)=0
We get rid of parentheses
12x^2-36x+13x+1=0
We add all the numbers together, and all the variables
12x^2-23x+1=0
a = 12; b = -23; c = +1;
Δ = b2-4ac
Δ = -232-4·12·1
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{481}}{2*12}=\frac{23-\sqrt{481}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{481}}{2*12}=\frac{23+\sqrt{481}}{24} $
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