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2x+4x/x=2
We move all terms to the left:
2x+4x/x-(2)=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
2x*x+4x-2*x=0
We add all the numbers together, and all the variables
2x+2x*x=0
Wy multiply elements
2x^2+2x=0
a = 2; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·2·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*2}=\frac{-4}{4} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*2}=\frac{0}{4} =0 $
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