A=(6x-35)B=(3x+53)

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Solution for A=(6x-35)B=(3x+53) equation: 



=(6A-35)=(3A+53)

We move all terms to the left:

-((6A-35))=0



We calculate terms in parentheses: -((6A-35)), so:

(6A-35)

We get rid of parentheses

6A-35

Back to the equation:

-(6A-35)



We get rid of parentheses

-6A+35=0

We move all terms containing A to the left, all other terms to the right

-6A=-35

A=-35/-6

A=5+5/6

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