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(A)=-A(A-80)
We move all terms to the left:
(A)-(-A(A-80))=0
We calculate terms in parentheses: -(-A(A-80)), so:We get rid of parentheses
-A(A-80)
We multiply parentheses
-A^2+80A
We add all the numbers together, and all the variables
-1A^2+80A
Back to the equation:
-(-1A^2+80A)
1A^2-80A+A=0
We add all the numbers together, and all the variables
A^2-79A=0
a = 1; b = -79; c = 0;
Δ = b2-4ac
Δ = -792-4·1·0
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6241}=79$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-79}{2*1}=\frac{0}{2} =0 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+79}{2*1}=\frac{158}{2} =79 $
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