0=(((2x-100)+(2x-100)+(2x-100)+(2x-100)))

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Solution for 0=(((2x-100)+(2x-100)+(2x-100)+(2x-100))) equation:



0=(((2x-100)+(2x-100)+(2x-100)+(2x-100)))
We move all terms to the left:
0-((((2x-100)+(2x-100)+(2x-100)+(2x-100))))=0
We add all the numbers together, and all the variables
-((((2x-100)+(2x-100)+(2x-100)+(2x-100))))=0
We calculate terms in parentheses: -((((2x-100)+(2x-100)+(2x-100)+(2x-100)))), so:
(((2x-100)+(2x-100)+(2x-100)+(2x-100)))
We calculate terms in parentheses: +(((2x-100)+(2x-100)+(2x-100)+(2x-100))), so:
((2x-100)+(2x-100)+(2x-100)+(2x-100))
We calculate terms in parentheses: +((2x-100)+(2x-100)+(2x-100)+(2x-100)), so:
(2x-100)+(2x-100)+(2x-100)+(2x-100)
We get rid of parentheses
2x+2x+2x+2x-100-100-100-100
We add all the numbers together, and all the variables
8x-400
Back to the equation:
+(8x-400)
We get rid of parentheses
8x-400
Back to the equation:
+(8x-400)
We get rid of parentheses
8x-400
Back to the equation:
-(8x-400)
We get rid of parentheses
-8x+400=0
We move all terms containing x to the left, all other terms to the right
-8x=-400
x=-400/-8
x=+50

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