2x+3=3(x-4)-2

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Solution for 2x+3=3(x-4)-2 equation: 



2x+3=3(x-4)-2

We move all terms to the left:

2x+3-(3(x-4)-2)=0



We calculate terms in parentheses: -(3(x-4)-2), so:

3(x-4)-2

We multiply parentheses

3x-12-2

We add all the numbers together, and all the variables

3x-14

Back to the equation:

-(3x-14)



We get rid of parentheses

2x-3x+14+3=0

We add all the numbers together, and all the variables

-1x+17=0

We move all terms containing x to the left, all other terms to the right

-x=-17

x=-17/-1

x=+17

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