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(5y-4)(7-y)=0
We add all the numbers together, and all the variables
(5y-4)(-1y+7)=0
We multiply parentheses ..
(-5y^2+35y+4y-28)=0
We get rid of parentheses
-5y^2+35y+4y-28=0
We add all the numbers together, and all the variables
-5y^2+39y-28=0
a = -5; b = 39; c = -28;
Δ = b2-4ac
Δ = 392-4·(-5)·(-28)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-31}{2*-5}=\frac{-70}{-10} =+7 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+31}{2*-5}=\frac{-8}{-10} =4/5 $
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